(4x^3-64x)/7

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Solution for (4x^3-64x)/7 equation: 


x in (-oo:+oo)

(4*x^3-(64*x))/7 = 0

(4*x^3-64*x)/7 = 0

4*x^3-64*x = 0

4*x*(x^2-16) = 0

1*x^2 = 16 // : 1

x^2 = 16

x^2 = 16 // ^ 1/2

abs(x) = 4

x = 4 or x = -4

4*x*(x-4)*(x+4) = 0

(4*x*(x-4)*(x+4))/7 = 0

( 4*x )

4*x = 0 // : 4

x = 0

( x+4 )

x+4 = 0 // - 4

x = -4

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 0, -4, 4 }

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